Steady State
MAT161 / Lecture 3
Lecture 3 · Barnett ch. 3 · about 45 min

Exponential and Logarithmic Functions

Compound growth, the number e, continuous compounding, and logarithms as the tool that solves for time or rate when it sits in an exponent.

By the end you can
  • Distinguish simple, compound and continuous growth, and compute future values for each
  • Explain what the number e represents and use continuous compounding
  • Apply the log laws to simplify exponential expressions
  • Solve for an unknown exponent (time or rate) using logarithms

Exponential growth

A linear function adds the same amount each period. An exponential function multiplies by the same factor each period: growth (or decay) proportional to the current level. This is the shape of compound interest, population growth, and inflation compounding.

Exponential functionFormula sheet →
f(x)=a bxf(x) = a\,b^x
aa
initial value, f(0)
bb
growth factor per period, b > 0, b \neq 1

Use it when a quantity grows or shrinks by the same percentage every period. b > 1 is growth; 0 < b < 1 is decay.

Worked example · Compound interest as an exponential function0/4

10,000 TL is deposited at 6% annual interest, compounded once a year. Find the balance after 5 years.

Compound interestFormula sheet →
A=P(1+rn)ntA = P\left(1 + \frac{r}{n}\right)^{nt}
PP
principal
rr
annual interest rate
nn
compounding periods per year
tt
years

Use it when interest compounds a fixed number of times per year, such as monthly (n=12) or quarterly (n=4).

Your turn

4,000 TL is invested at 8% annual interest, compounded quarterly. What is the balance after 2 years? (Round to the nearest lira.)

The number e and continuous compounding

As the number of compounding periods nn grows without bound, (1+r/n)nt(1 + r/n)^{nt} approaches a limit built from a special constant, e≈2.71828e \approx 2.71828, the base of continuous growth.

Continuous compoundingKey formulaFormula sheet →
A=P ertA = P\,e^{rt}
PP
principal
rr
annual (continuous) interest rate
tt
years
ee
Euler's number, \approx 2.71828

Use it when a question says continuously compounded, or you need the theoretical upper limit of compounding more and more often.

Your turn

5,000 TL is invested at 5% continuously compounded interest. What is the balance after 10 years? (Round to the nearest lira.)

Logarithms: undoing an exponent

A logarithm answers the question “to what power?” It is the inverse of an exponential function, exactly the same relationship as a function and its inverse from the previous lesson.

Definition of a logarithmFormula sheet →
log⁡b(x)=y  ⟺  by=x\log_b(x) = y \iff b^y = x
bb
base, b > 0, b \neq 1
xx
the argument, x > 0
yy
the exponent that produces x

Use it when you need to convert between exponential form and logarithmic form, or as a first step before applying the log laws.

Two bases dominate economics: base 10 (log⁡\log) and base ee (the natural logarithm, ln⁡\ln).

Log lawsRulesFormula sheet →
ln⁡(MN)=ln⁡M+ln⁡Nln⁡ ⁣(MN)=ln⁡M−ln⁡Nln⁡(Mp)=p ln⁡M\ln(MN) = \ln M + \ln N \qquad \ln\!\left(\frac{M}{N}\right) = \ln M - \ln N \qquad \ln(M^p) = p\,\ln M
M,NM, N
positive numbers
pp
any real exponent

Use it when a variable sits inside an exponent, or a product/quotient/power needs to be broken apart before solving.

Check your understanding

Which is the correct simplification of ln⁡(x3y)\ln(x^3 y)?

Solving for time: when the unknown is an exponent

The whole reason to reach for logs in business math is to solve for a variable that sits in the exponent, such as the number of years needed to double an investment.

Worked example · Solving for time algebraically0/5

How many years does it take 8,000 TL to grow to 12,000 TL at 7% annual interest, compounded annually?

Your turn

A quantity growing continuously at a rate of 4% a year doubles when e0.04t=2e^{0.04t} = 2. How many years does it take to double? (Round to one decimal place.)

Rule of 70 (approximation)Formula sheet →
tdouble≈70100rt_{\text{double}} \approx \frac{70}{100r}
rr
continuous annual growth rate (as a decimal)
tdoublet_double
approximate doubling time in years

Use it when you need a quick mental estimate of doubling time without a calculator, such as for inflation or GDP growth.

Exam practice

Exam question 1

6,000 TL is invested at 5% annual interest, compounded annually. What is the balance after 3 years? (Round to the nearest lira.)

Exam question 2

12,000 TL is invested at 6% continuously compounded interest for 4 years. What is the balance? (Round to the nearest lira.)

Exam question 3

Simplify ln⁡(e5x)\ln(e^{5x}).

Exam question 4

How many years does it take 3,000 TL to grow to 5,000 TL at 8% annual interest, compounded annually? (Round to one decimal place.)

Summary and review

Review deck · 12 cards0/12 mastered