Steady State
MAT161 / Lecture 10
Lecture 10 · Barnett ch. 4 · about 45 min

First Derivative and Graphs

Reading a function's shape from the sign of its derivative: where it rises and falls, its critical points, and the first-derivative test that tells local maxima from local minima.

By the end you can
  • Determine intervals where a function is increasing or decreasing from the sign of f prime
  • Find the critical numbers of a function
  • Apply the first-derivative test to classify each critical point
  • Sketch the shape of a profit or cost function using a sign chart

The sign of the derivative tells you the shape

The derivative is a rate of change. Its sign at a point tells you whether the function is rising or falling there, which is enough information to sketch the overall shape of a curve without plotting dozens of points.

Increasing and decreasingRulesFormula sheet →
f′(x)>0 on an interval  ⇒  f is increasing theref′(x)<0  ⇒  f is decreasing theref'(x) \gt 0 \text{ on an interval} \;\Rightarrow\; f \text{ is increasing there} \qquad f'(x) \lt 0 \;\Rightarrow\; f \text{ is decreasing there}
f′(x)f'(x)
the derivative of f, whose sign on an interval tells you the direction f is moving

Use it when you need to describe where a function rises or falls, such as where profit is growing versus shrinking.

Check your understanding

A firm's profit function satisfies P′(x)<0P'(x) \lt 0 for all xx between 300 and 500 units. What does this say about profit in that range?

Critical numbers

A critical number is a value in the domain of ff where f′(x)=0f'(x) = 0 or f′(x)f'(x) does not exist. These are the only candidates for local maxima and minima.

Critical numbersDefinitionFormula sheet →
f′(c)=0orf′(c) does not exist, with c in the domain of ff'(c) = 0 \quad \text{or} \quad f'(c) \text{ does not exist, with } c \text{ in the domain of } f
cc
a critical number of f

Use it when you are looking for possible local maxima or minima of a function, as the first step before the first-derivative test.

Worked example · Finding critical numbers0/4

Find the critical numbers of P(x)=−x3+15x2−48x+200P(x) = -x^3 + 15x^2 - 48x + 200 (a profit function).

Your turn

Find the positive critical number of f(x)=x3−12x+5f(x) = x^3 - 12x + 5.

The first-derivative test

Once you have the critical numbers, check the sign of f′f' on each side of each one. A sign change tells you what kind of turning point it is.

First-derivative testKey ruleFormula sheet →
f′:+→− at c  ⇒  local max at cf′:−→+ at c  ⇒  local min at cf' : + \to - \text{ at } c \;\Rightarrow\; \text{local max at } c \qquad f' : - \to + \text{ at } c \;\Rightarrow\; \text{local min at } c
+→−+ \to -
f' is positive just before c and negative just after
−→+- \to +
the reverse

Use it when you have found critical numbers and need to classify each one, or a question directly asks for local extrema.

If f′f' does not change sign at cc (say, positive on both sides), then cc is neither a local max nor a local min — often a point where the curve flattens momentarily and keeps going the same direction, such as f(x)=x3f(x) = x^3 at x=0x = 0.

Worked example · Classifying with a sign chart0/5

Continue the profit example: P′(x)=−3(x−2)(x−8)P'(x) = -3(x-2)(x-8), with critical numbers 2 and 8. Classify each with a sign chart.

Your turn

For P(x)=−x3+15x2−48x+200P(x) = -x^3 + 15x^2 - 48x + 200 from the worked example, what is P(8)P(8), the local maximum profit?

Increasing/decreasing intervals in one picture

Worked example · Full sign chart summary0/4

Summarise the shape of P(x)=−x3+15x2−48x+200P(x) = -x^3 + 15x^2 - 48x + 200 using the sign chart from before.

Check your understanding

A function has critical numbers at x=−1x = -1 and x=4x = 4. f′f' is positive on (−∞,−1)(-\infty, -1), positive on (−1,4)(-1, 4), and negative on (4,∞)(4, \infty). What kind of critical point is x=−1x = -1?

Exam practice

Exam question 1

Find the positive critical number of f(x)=x3−27xf(x) = x^3 - 27x.

Exam question 2

For f(x)=x3−27xf(x) = x^3 - 27x, use test points to classify x=3x = 3.

Exam question 3

Revenue is R(x)=90x−0.3x2R(x) = 90x - 0.3x^2. Find the critical number of R.

Exam question 4

A cost function has C′(x)>0C'(x) \gt 0 for all x>0x \gt 0, with no critical numbers in the domain. What does this tell you about the cost curve?

Summary and review

Review deck · 8 cards0/8 mastered