Steady State
MAT161 / Lecture 2
Lecture 2 · Barnett ch. 1 to 2 · about 45 min

Linear and Quadratic Functions

Straight-line cost and revenue models, break-even analysis, and the parabola that appears whenever a linear price meets a linear cost: how to find its vertex and its roots without a graph.

By the end you can
  • Write a linear function from a slope and a point, or from two points, and interpret the slope economically
  • Find the break-even quantity where a linear cost and revenue function cross
  • Put a quadratic into vertex form and read off its maximum or minimum
  • Use the quadratic formula to find break-even points for a quadratic profit function

Linear functions

A linear function has a constant rate of change: every extra unit of xx changes yy by the same amount, mm.

Slope-intercept formFormula sheet →
y=mx+by = mx + b
mm
slope, the change in y per unit change in x
bb
y-intercept, the value of y when x = 0

Use it when you know the rate of change and the starting value. In cost functions, m is the variable cost per unit and b is the fixed cost.

Economically, mm is a marginal quantity (cost per extra unit, or the change in price per extra unit sold) and bb is a baseline quantity (fixed cost, or a starting price).

Worked example · Building a linear cost function from data0/4

A bakery's total cost was 800 TL when it baked 50 loaves, and 1,100 TL when it baked 100 loaves. Assume cost is linear in output. Find the cost function.

Check your understanding

A firm's cost function is C(x)=12x+3000C(x) = 12x + 3000. What does the number 3000 represent?

Break-even analysis with two lines

Break-even is the output level where total revenue equals total cost: R(x)=C(x)R(x) = C(x). Below it the firm loses money; above it, profit is positive.

Break-even pointConditionFormula sheet →
R(x)=C(x)R(x) = C(x)
R(x)R(x)
px = price times quantity
C(x)C(x)
variable cost + fixed cost

Use it when revenue and cost are both linear in x. Solve the resulting linear equation for x.

Worked example · Solving for break-even0/4

A workshop sells a product for 50 TL each. Cost is C(x)=30x+4000C(x) = 30x + 4000. Find the break-even quantity.

Your turn

A café sells coffee at 60 TL a cup. Its cost function is C(x)=25x+7000C(x) = 25x + 7000. What is the break-even quantity, in cups?

Quadratic functions

A quadratic function has a squared term and graphs as a parabola. In business, a quadratic often appears when a linear demand curve meets a linear cost: revenue =p(x)⋅x= p(x)\cdot x becomes quadratic in xx once price itself depends on xx.

Standard formFormula sheet →
f(x)=ax2+bx+cf(x) = ax^2 + bx + c
aa
shapes the curve (a > 0 opens upward, a < 0 opens downward)
b,cb, c
shift and position the curve

Use it when you are given a quadratic in expanded form and need to identify its shape before finding the vertex.

If a>0a \gt 0 the parabola opens upward and has a minimum (useful for a cost or average-cost curve). If a<0a \lt 0 it opens downward and has a maximum (useful for revenue or profit).

Vertex form: finding the max or min without calculus

Vertex of a parabolaKey formulaFormula sheet →
x∗=−b2af(x∗)=c−b24ax^* = -\frac{b}{2a} \qquad f(x^*) = c - \frac{b^2}{4a}
x∗x^*
the input at the vertex
f(x∗)f(x^*)
the maximum (a<0) or minimum (a>0) value

Use it when you have a quadratic profit, revenue or cost function and need the optimal quantity and the optimal value, without derivatives.

Worked example · Maximising a quadratic revenue function0/4

Demand is p=100−2xp = 100 - 2x, so revenue is R(x)=x(100−2x)=−2x2+100xR(x) = x(100 - 2x) = -2x^2 + 100x. Find the revenue-maximising quantity and the maximum revenue.

Your turn

A firm's average cost is Cˉ(x)=0.5x2−20x+300\bar C(x) = 0.5x^2 - 20x + 300. At what output x is average cost minimised?

Try it: shape the profit parabola

Raise the net price bb and the vertex moves up and right: a higher price raises both the profit-maximising quantity and the maximum profit. Raise the fixed cost cc and the whole curve shifts down: the vertex height falls and the break-even points move apart, since more revenue is now needed just to cover costs.

The quadratic formula: break-even for a curved profit

When profit is quadratic, break-even points are the roots: the xx values where P(x)=0P(x) = 0. Factoring is not always possible, so use the quadratic formula.

Quadratic formulaFormula sheet →
x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
a,b,ca, b, c
the coefficients of ax^2 + bx + c
b2−4acb^2 - 4ac
the discriminant

Use it when a quadratic profit or revenue function does not factor easily, or a question directly asks for its roots (break-even points).

The discriminant b2−4acb^2 - 4ac tells you how many real break-even points exist: positive gives two, zero gives exactly one (the vertex touches the axis), and negative means the curve never crosses zero — the firm never breaks even (if a<0a \lt 0 and the vertex is below zero) or never loses money (if a>0a \gt 0 and the vertex is above zero).

Worked example · Finding break-even with the quadratic formula0/5

Profit is P(x)=−x2+26x−120P(x) = -x^2 + 26x - 120. Find the break-even quantities.

Check your understanding

A quadratic profit function has discriminant b2−4ac=−50b^2 - 4ac = -50. What does this tell you?

Exam practice

Exam question 1

A line passes through (10, 220) and (30, 340). Find its slope.

Exam question 2

Revenue is R(x)=−3x2+240xR(x) = -3x^2 + 240x. Find the revenue-maximising quantity x.

Exam question 3

Using the same revenue function R(x)=−3x2+240xR(x) = -3x^2 + 240x, what is the maximum revenue?

Exam question 4

Profit is P(x)=−2x2+20x−70P(x) = -2x^2 + 20x - 70. What can you conclude from its discriminant?

Summary and review

Review deck · 11 cards0/11 mastered